
(Last modified: Friday, April 25, 2008, 11:00 AM )
I'll use Maple syntax for some of the mathematical notation on this page.
All section and page numbers refer to sections from Calculus from Graphical, Numerical, and Symbolic Points of View, Volume 1, 2nd Edition, by Ostebee and Zorn.
Due Friday 4/25 at 9am
Section 2.5 Differential Equations; Modelling Motion
Reading questions:
SS says (but I re-ordered, to make it a bit more readable on the web)
Since y(x)=x^(1/3) makes the DE true, it is one solution to the DE.
y'(x) = (1/3)x^(-2/3) = 1/(3*x^(2/3)) = 1/(3*(x^(1/3))^2) = 1/(3*y^2)
SS also says:
if y'(x)=5/x^2+4 then y(x)=(-5/x)+4x+C, so y(1)=-5+4+C =-1+CSince y(1) has to equal 12 then C must equal 13...
so y(x)=(-5/x)+4x+13
Due Friday 4/18 at 9am
Section 5.6 Approximating Sums: The Integral as a Limit
Reading questions:
NT says:
A Riemann sum allows you to closely approximate the signed area. It finds the area of a series of rectangles that approximate the shape of the f(x).
GC says:
Ln will over estimate and Rn will underestimate.
Due Monday 4/14 at 9am
Section 5.4 Finding Antiderivatives: The Method of Substitution
Reading questions:
MS and AK say:
A definite integral looks to find the signed area of a function over a specific interval.Indefinite integrals are used to denote the ÒfamilyÓ of all possible antiderivatives of f.
AJK says:
The chain rule
DH says:
The first step is to choose a function u=u(x) and come up with a function du=u'(x)dx. Then substitute u and du in to the original integral to produce a new integral.The second step is to antidifferentiate in u.
Then resubstitute --substitute back to eliminate u.
Due Wednesday 4/9 at 9am
Section 5.3 The Fundamental Theorem of Calculus
Reading questions:
JS says:
First, I would find the anti-derivative, which is: x^4/4+4x.Then, since we want to find the area from 0 to 3, which is calculated using F(b) - F(a), this area turns out to be 32.25.
NM says:
Every continuous function has an anti-derivative, since Af must always be an anti-derivative of f.
NW says:
The area between the function and the x axis is the antiderivative of the function, so area is increasing when the original function is positive, and decreasing when it is negative.
It is decreasing at all values less than 5/3 and increasing on all values larger then that.
BF says:
It doesn't.
Due Monday 4/7 at 9am
Section 5.2 The Area Function
AK says:
It measures the signed area defined by f (and the horizontal axis) from a to x.
NP says:
Af(1) = 1/2 since 1/2*1*1= 1/2![]()
Due Friday 4/4 at 9am
Section 5.1 Areas and Integrals
Reading questions:
DD says:
The integral of a function f from x=a to x=b measures signed area. The integral of f from x=a to x=b implies a direction : x starts at a and ends at b.
I say:
The integral of 5x from -1 to 3 is the signed area of the region between the line y=5x and the x-axis, from x=-1 to x=3. This signed area is shown to the left. Area below the x-axis is negative, area above the x-axis is positive. More of the area is above the x-axis than is below, and so the total area turns out to be positive.
Due Wednesday 4/2 at 9am
Section 4.9 Why Differentiability: The Mean Value Theorem
Reading questions:
KG says:
The hypotheses of the Man Value Theorm state that the function y=f(x) must be continous on the closed internal and differential on the open interval.
AB says:
(f(b)-f(a))/(b-a)gives the slope of the line joining the endpoints of the curve. for an x between [a,b], the derivative must equal the slope of the line joining the endpoints.
SP says:
If you are averaging 60 mph in a car over a given period of time, you must have been going exactly 60 mph at an instant within that time period.
Due Friday 3/28 at 9am
Section 4.8 Why Continuity Matters
Reading questions:
NP says:
The hypotheses of the Intermediate Value Theorem: f is continuous on the closed, bounded interval [a,b], and y is any number between f(a) and f(b).
CM says:
The conclusion of the Intermediate Value Theorem is that for some input c between a and b, f(c)=y.In other words, as JL says:
On the way from (a,f(a)) to (b,f(b)), the graph of f crosses every horizontal line between y= f(a) and y= f(b).
Due Wednesday 3/19 at 9am
Section 4.7 Building Polynomials to order: Taylor Polynomials
Reading questions:
AL says:
We find a Taylor polynomial of a function because Taylor polynomials approximate other (non-polynomials) functions.A Taylor polynomial would be useful if a function is ill-behaved, complicated, or poorly understood. Thus you replace it with a Taylor polynomial g(x). By replacing a function with a Taylor polynomial you can approximate the difficult equation. This allows you go get a general idea/understanding of the function.
SK says:
To build a Taylor Polynomial of order n at x0, you first need to find n derivatives of f(x). Then, you take the sum illustrated in the equation below:Pn(x)=f(x0) + f'(x0)(x-x0) + f''(x0)/2! (x-x0)^2... etc.
Due Monday 3/17 at 9am
Section 4.3 Optimization
Reading questions:
AB says:
On a closed interval [a,b], a continuous function can achieve its maximum or minimum value only at critical points in (a,b) or at endpoints of [a,b].
MS says:
Objective functions describe the quantities to be maximized or minimized
A constraint function describes a condition that must be satisfied by the variables in an optimization problem.
Due Monday 3/3 at 9am
Section 3.2 Composition and the Chain Rule
Reading questions:
Explain what is wrong with the following calculations and fix them.
NT says:
In the example, the product rule was erroneously used instead of the chain rule.f'(x)= cos(x^2)*2x.
BF says:
The chain rule was not applied to find the derivative of the function. You forgot to multiply by the derivative of 3x.So, g'(x)= 3*exp(3*x).
KP says:
According to the chain rule you have to take the derivative of the outside function composed with the inside function and then multiply it by the derivative of the inside function.THe correction would be h'(x)= 3*(sin(x))^2*cos(x).
Due Friday 2/29 at 9am
Section 3.1 Algebraic Combinations: The Product and Quotient Rules
Reading questions:
Explain what is wrong with the following calculations and fix them.
MTS says:
According to the product rule, the calculation should look like:
2x*sin(x)+x^2*cos(x)
SS says:
In the derivative above, you took the derivative of the first part and divided it by the derivative of the second part. You were supposed to use the quotient rule.The derivative below is correct:
g'(x) = (x^2+1)(cos(x))-(sin(x))(2x) / (x^2+1)^2
-->
Due Wednesday 2/27 at 9am
Section 2.7 Derivatives of Trigonometric Functions: Modeling Oscillation
Reading questions:
Combining two answers, ACC and NM say:
Since cos(0)=1, we can re-write the expression as
limit( (cos(h)-cos(0))/(h-0), h=0). This defines the derivative of the cosine function at x=0.Because the cosine graph is horizontal at x=0, the limit of ( (cos(h)-1)/h, h=0) is zero.
EP says:
The limit( sin(h)/h, h=0) defines the derivative of the sine function at x=0. After looking at the slope of the curve y=sin x near x=0, we can conclude that the derivative is 1.
MPS says:
We care about these two limits because they help us define the derivatives of the sin and cos functions.
VB says:
(sin(2x))' =2cos(2x)
Due Monday 2/25 at 9am
Section 2.6 Derivatives of Exponential and Logarithmic Functions; Modelling Growth
Reading questions:
KG says:
The 47th derivative of f(x)= exp(x) is exp(x), it doesn't change.
AK says:
A compound-interest bearing account exhibits exponential growth since it grows at a rate proportional to its size.
Due Friday 2/22 at 9am
Section 2.4 Using Derivative and Antiderivative Formulas
Reading questions:
AK says:
A function F is an antiderivative of f if FÕ(x) = f(x). The process of recovering a function F(x) from its derivative f(x) is called antidifferentiation.
DH adds:
To find the antiderivative, you do the complete opposite as when finding the derivative.For example, the antiderivative of 5x^27+32x^5+10 is 5x^28/28+32x^6/6+10x. Instead of subtracting (from the power),you add, and instead of multiplying by the power, you divide. You must remember to take care of the power first before doing the dividing.
SK says:
f(x)=3x^2 has an infinite number of antiderivatives because adding a constant to any function F has no effect on F'.
Due Wednesday 2/20 at 9am
Section 2.3 Limits
Reading questions:
AMC says:
g(x) is not defined at x=3 because that would mean the denominator would be zero and you can't divide anything by zero.
CM says:
The limit at x=3 is 6 because the equation will equal a number close to 6 for any number close to x=3.AS adds:
Lim x->3g(x)= Limx->3 (x+3) =6
DD says:
F(x)=|x| is continuous because even though there is a kink it doesnÕt mean that the graph is broken.
Due Friday 2/15 at 9am
Section 2.2 Derivatives of Power Functions and Polynomials
Reading questions:
PE says:
f '(x)=3x^2
ACC says:
It does not exist at x=0 because the graph has a vertical tangent line.
Due Monday 2/11 at 9am
Section 2.1 Defining the Derivative
Reading questions:
AJL says:
Use the difference quotient.If f(x)=x^3, (f(4)-f(-2))/6=12.
ASL says:
( f(a+h) - f(a) )/h measures the slope of the secant line that is created by two points on any given graph.
The difference quotient measures the average rate of change of the function f from x=a to x=a+h.
VB says:
To find the average rate of change of f from x=-2 to x=4, I use the same method as question one. f(4)-f(-2)/6= 12. The average rate of change is found by using the difference quotient.
Due Friday 2/8 at 9am
Section 1.7 The Geometry of Higher Order Derivatives
Reading questions:
Use the graphs of f, f ', f '' in Figure 3 on page 67.
AG says:
When f'' is positive, f' is increasing which says that the function f is concave up. When f'' is negative, f' is decreasing which means the function f is concave down.
KP says:
The graph of f will be concave up when f' is increasing, and f will be concave down when f' is decreasing.At point B on graph of f', the graph is changing direction from decreasing to increasing, and at point B on the graph of f, f is changing concavity.
Due Wednesday 2/6 at 9am
Section 1.6 The Geometry of Derivatives
Reading questions:
Look at the graph of f ' in Example 2.
NT says:
f has stationary points at x= -1, x=0, and x=1 because on the graph of f ' the graph crosses the x axis. This means that the slope of f at these points is 0, making them stationary points (of f).
AB says:
f is increasing from [-1.5,-1) and from (1, 1.5) because the derivative is positive, therefore the slope of f is positive, so f is increasing in those intervals.
GC says:
f is concave up from -0.5 to 0 and from 0.5 to infinity because these are the points where the f '(x) graph slopes upward.
Due Monday 2/4 at 9am
Section 1.5 Estimating the Derivative
Reading questions:
JS says:
The term locally linear means that by zooming in on any graph will expose a straight line, or a near straight line. Even if the graph appears curvy from a distance, by zooming in, that small piece of the graph will become straight enough to discern its slope and therefore its derivative.
EP says:
The derivative of f(x)=|x| does not exist at x=0 because the f(x)=|x| function has a kinked graph, which cannot be straightened out by zooming. If zooming has no effect at all on the kink at the origin, then, in mathematical terms f'(0) does not exist.
Due Friday 2/1 at 9am
Section 1.4 Amount Functions and Rate Functions: The Idea of the Derivative
Reading questions:
Look at the graphs of P(t) and V(t) in Figure 1 on page 37.

EB says:
The derivative of P at t=5 is negative because v(t) is equal to the derivative of p(t) and on the graph v(t)=-30 when t=5.
BF says:
the second derivative of P is represented by A(t) -- also known as the derivative of V(t). at t=5 on the V(t) graph, the velocity is increasing, so A(t) would be positive.
JL says:
t=3, t=6.75. These are both points where velocity crosses the x-axis, meaning she is changing from traveling eastward to westward.
Due Monday 1/28 at 9am
Problem Set Guidelines
Section 1.3 A Field Guide to Elementary Functions
SS says:
The functions f(x)=3^x and g(x)=log[3](x) are related because they are inverses of each other. Inverses of each other means that they reflect across the line y=x.
PY says:
Sin(x) has the following properties: Its domain is negative infinity to positive infinity, and its range is [-1,1]. The function Sin(x) is considered odd and repeats itself on intervals of 2pi.
Due Friday 1/25 at 9am
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Section 1.1: Functions, Calculus Style
Section 1.2: Graphs
Reading questions:
Let f(x)=x^2.
NW says:
The graph y=f(x)+3=x^2+3 is just the graph of f(x)=x^2 shifted up three units on the y-axis, with an x-intercept at (0,3). Adding a constant "a" to a function f(x) results in a vertical translation g(x)=f(x)+a
NP says:
The graph y = f(x + 3) = (x + 3)^2 is related to the graph of y = f(x) in the sense that the graph y = f(x + 3) = (x + 3)^2 is a leftward shift of the f(x) graph. This type of shift is known as a horizontal translation, where the graph y = f(x + a) is the result of shifting the f-graph a units to the left.
SP says:
f(x) and f(x)+2 are both even because when you replace (x) with (-x) the equation will still equal f(x) (or f(x)+2). f(x+2)is neither even or odd because when you replace (x) with (-x) and square it you come up with different results:
(-x+2)^2=x^2-4x+4,
while (x+2)^2=x^2+4x+4.
Janice Sklensky
Wheaton College
Department of Mathematics and Computer Science
Science Center, Room 109
Norton, Massachusetts 02766-0930
TEL (508) 286-3973
FAX (508) 285-8278
jsklensk@wheatonma.edu